72x^2+2x-35=0

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Solution for 72x^2+2x-35=0 equation:



72x^2+2x-35=0
a = 72; b = 2; c = -35;
Δ = b2-4ac
Δ = 22-4·72·(-35)
Δ = 10084
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{10084}=\sqrt{4*2521}=\sqrt{4}*\sqrt{2521}=2\sqrt{2521}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{2521}}{2*72}=\frac{-2-2\sqrt{2521}}{144} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{2521}}{2*72}=\frac{-2+2\sqrt{2521}}{144} $

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